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6 August, 10:22

A 5.0g sample of aluminum with a specific heat of 0.90 j/g was heated from 22.1^c to 32.1^c. How much heat to the nearest joule did the aluminum gain?

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  1. 6 August, 10:35
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    The heat to the nearest joules that aluminium gain is calculated as below

    Q (heat) = M (mass) x c (specific heat capacity) x delta T (change in temperature)

    M=5.0 g

    c=0.90 j/g/c

    deltat T = 32.1 - 22.1=10c

    q = 5.0 g x 0.90 j/g/c x 10 c = 45 joules is the one gained by Alluminium
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