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22 March, 22:42

How many grams are in 4.23 x 1024 atoms of He?

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  1. 22 March, 22:44
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    28.11g

    Explanation:

    Step 1:

    Background understanding:

    From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This also indicates that 1 mole of helium (He) contains 6.02x10^23 atoms.

    1 mole of He = 4g

    Step 2:

    Determination of the mass of He that contain 4.23x10^24 atoms. This is illustrated below:

    4g of He contains 6.02x10^23 atoms.

    Therefore Xg of He will contain 4.23x10^24 atoms i. e

    Xg of He = (4x4.23x10^24) / 6.02x10^23

    Xg of He = 28.11g

    Therefore, 28.11g of He contains 4.23x10^24 atoms
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