Determine the equilibrium pH and speciation (concentration of each species) of the following two solutions. Neglect activity corrections. Species added Total concentration (solution a) HCl 10-3 M (solution b) NaCl 10-3 g.

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Raegan Singh

Chemistry

25 October, 23:35

Determine the equilibrium pH and speciation (concentration of each species) of the following two solutions. Neglect activity corrections. Species added Total concentration (solution a) HCl 10-3 M (solution b) NaCl 10-3 g.

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Whispy · Answer 1

HCl solution - H30 + and Cl ions. pH 3

NaCl - Na + and Cl-. pH 7

Explanation:

a) HCl solution - the hydrogen ion combines with water molecule to form the hydronium molecule which is responsible for acidity. The chloride ion is also found in solution.

pH = - log [H+] = - log (10^-3) = 3

b) NaCl 10-3 g. The solid dissocates in water forming the Na + and Cl - ions. None of these ions affect pH