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4 June, 23:32

what is the molecular formula of a compound with the empirical formula of P2O3 and a gram molecular mass of 284 grams?

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  1. 4 June, 23:37
    0
    The answer is: the molecular formula of a compound is P₄O₁₀.

    M (P₂O₅) = 2 · Ar (P) + 5 · Ar (O) · g/mol.

    M (P₂O₅) = 2 · 31 + 5 · 16 · g/mol.

    M (P₂O₅) = 142 g/mol; molar mass of empirical formula.

    M (PₓOₙ) = 284 g/mol; molecular mass of unknown compound.

    M (PₓOₙ) : M (P₂O₅) = 284 g/mol : 142 g/mol.

    M (PₓOₙ) : M (P₂O₅) = 2 : 1.
  2. 5 June, 00:01
    0
    P5O8

    Explanation:

    The formula to be used here is

    (mass of the emperical formula) n = molecular mass

    n is a number that is unknown

    The atomic mass of phosphorus (P) is 31 g/mol while that of oxygen is 16 g/mol

    molecular mass of the compound is 284g

    (P2O3) n = 284g

    [ (31 x 2) + (16 x 3) ]n = 284

    (110) n = 284

    n = 284/110

    n = 2.58

    If n = 2.58, the molecular formula is (P2O3) 2.58

    which is then P (2 x 2.58) = P (5.16) ⇔ P5 and

    O (3 x 2.58) = O (7.74) ⇔ O8

    = P5O8

    NOTE: 5.16 was rounded up to 5 while 7.74 was rounded up to 8
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