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29 October, 00:49

Calculate the volume in liters of a 4.6 x 10^-5 M mercury iodine solution that contains 500. mg of mercury (II) iodide HgI2. Round your answer to 2 significant digits.

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  1. 29 October, 01:19
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    V HgI2 = 23.92 L

    Explanation:

    ∴ C HgI2 = 4.6 E-5 M = 4.6 E-5 mol/L

    ∴ m HgI2 = 500 mg = 0.500 g

    ∴ Mw HgI2 = 454.4 g/mol

    ⇒ V HgI2 = 0.500g * (mol / 454.4 g) * (L / 4.6 E-5 mol)

    ⇒ V HgI2 = 23.92 L
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