Hydrochloric acid and calcium carbonate react to form calcium chloride, carbon dioxide, and water. If you being with 1.25 L of 1.20 M calcium carbonate and a stoichiometric amount of hydrochloric acid, how many grams of carbon dioxide will be formed

44.01 grams of carbon dioxide will be formed

Explanation:

This is the balance equation:

2HCl (aq) + CaCO₃ (aq) → CaCl₂ (aq) + CO₂ (g) + H₂O (l)

Firstly, let's find out the moles for the salt, in the reactants.

Molarity. volume = Moles

1.2 mol/L. 1.25L = 1.5 moles

The stoichiometric amount of hydrochloric acid is 2.

Ratio between reactants is 2:1

If I have 2 moles of HCl, I need 1 mol of carbonate. I have 1.5 moles, so the salt is in excess and the limiting is the HCl.

Ratio between HCl and CO₂ is 2:1

If I have 2 moles of HCl, I make 1 mol of CO₂

The grams formed are just, the molar mass.

44.01 g