If 36.0 g of mgso4⋅7h2o is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

Question

Deven Barnett

Chemistry

6 April, 17:11

If 36.0 g of mgso4⋅7h2o is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

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Answers (1)

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Taylor Hudson · Answer 1

Answer is: mass of anhydrous magnesium sulfate 17,50 grams will remain.

m (MgSO₄·7H₂O) = 36,0 g.

m (MgSO₄) = ?

Make proportion: m (MgSO₄) : m (MgSO₄·7H₂O) = M (MgSO₄) : M (MgSO₄·7H₂O).

m (MgSO₄) : 36,0 g = 120,36 g/mol : 247,47 g/mol.

m (MgSO₄) = 17,50 g.