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5 July, 08:06

What volume of 0.100M of sodium trioxonitrate (v) contains 5g of a solute? (Na=23, N=14, O=16)

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  1. 5 July, 08:18
    0
    0.79L

    Explanation:

    From the question given, the following were obtained:

    Molarity = 0.1M

    Molar Mass of HNO3 = 1 + 14 + (16x3) = 1 + 14 + 48 = 63g/mol

    Mass of HNO3 = 5g

    Number of mole = ?

    Number of mole = Mass / Molar Mass

    Number of mole of HNO3 = 5/63 = 0.079mole

    Now we can obtain the volume of the solution as follows:

    Molarity = 0.1M

    Mole = 0.079mole

    Volume = ?

    Molarity = mole/Volume

    Volume = mole / Molarity

    Volume = 0.079/0.1

    Volume = 0.79L
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