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23 February, 01:43

An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to - 5°C. Assume that there is no volume change in the tire. How does the tire pressure change in response to the temperature change?

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  1. 23 February, 01:47
    0
    1) it decreases

    2) 2.65 atm
  2. 23 February, 02:02
    0
    The tire pressure drops to 2.65 atm.

    Step-by-step explanation:

    Volume remains constant, so we can use Gay-Lussac's Law.

    p₁/T₁ = p₂/T₂ Multiply both sides by T₂

    p₂ = p₁ * T₂/T₁

    dа ta:

    p₁ = 3.00 atm; T₁ = 30.0 °C

    p₂ = ?; T₂ = - 5 °C

    Calculations:

    (a) Convert the temperatures to kelvins

    T₁ = 30.0 + 273.15 = 303.15 K

    T₂ = - 5 + 273.15 = 268.15 K

    (b) Calculate the new pressure

    p₂ = 3.00 * 268.15/303.15

    p₂ = 3.00 * 0.8845

    p₂ = 2.65 atm

    The pressure drops to 2.65 atm.
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