Describe the redox reaction. Check all that apply 2AI (s) + 3ZnCI2 (g) → 3Zn (s) + 2AICI3 (aq).

Aluminum atoms transfer electrons to chlorine atoms.

Zinc is reduced.

Zinc is the reducing agent.

The oxidation number of chlorine does not change.

Aluminum is oxidized.

Answer: B, D, E

Zinc is reduced.

The oxidation number of chlorine does not change.

Aluminum is oxidized.

Explanation:

For the reaction:

2AI (s) + 3ZnCI₂ (g) → 3Zn (s) + 2AICI₃ (aq).

For the elements in the reactants side:

Al has (0) oxidation state and converted to (+3) oxidation state in the products (AlCl₃), which means Al is oxidized and it is the reducing agent.

So, we can check that: Aluminum is oxidized.

Zn has the oxidation state (+2) in the reactants side (ZnCl₂) and converted to (0) in the products side (Zn), which means that Zn is reduced and it is the oxidizing agent.

So, we can check that: Zinc is reduced.

and can not check: Zinc is the reducing agent.

The oxidation state of Cl does not change, it is the same in both sides (-1).

So, we can check: The oxidation number of chlorine does not change.

and can not check: Aluminum atoms transfer electrons to chlorine atoms.

So, the choices will be:

Zinc is reduced.

The oxidation number of chlorine does not change.

Aluminum is oxidized.