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15 July, 19:32

if the volume of a gas at 200.0 kPa is 25.5 L. what is the new volume of the gas at 11.2 atm of pressure?

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  1. 15 July, 19:48
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    Answer: 2.22 litres

    Explanation:

    Given that,

    Original pressure of gas (P1) = 200.0 kPa

    [Since final pressure is given in atmosphere, Convert 200.0 kPa to atmosphere

    If 101.325 kPa = 1 atm

    200.0 kPa = 200.0/101.325

    = 1.9738 atm]

    Original volume of oxygen O2 (V1) = 25.5L

    New pressure of gas (P2) = 11.2 atm

    New volume of gas (V2) = ?

    Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

    P1V1 = P2V2

    0.9738 atm x 25.5L = 11.2 atm x V2

    24.8319 atm•L = 11.2 atm•V2

    Divide both sides by 11.2 atm to get V2

    24.8319 atm•L/11.2 atm = 11.2 atm•V2/11.2 atm

    2.217 L = V2

    [Round 2.217L to the nearest hundredth as 2.22L]

    Thus, the new volume of the gas at 11.2 atm of pressure is 2.22 litres
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