Ask Question
11 April, 08:30

How much heat is required to convert 422 g of liquid h2o at 23.5 °c into steam at 150 °c?

+1
Answers (1)
  1. 11 April, 08:55
    0
    Heat is given by multiplying the specific heat capacity of a substance by mass and the change in temperature. The heat capacity of water is Approximately 4184 J/K/C.

    Therefore, heat = mc0 mass in kg

    = (422/1000) * 4184 * (100-23.5)

    = 135072.072 J

    Latent heat of vaporization is 2260 kJ/kg

    Thus the heat will be 0.422 * 2260000 = 953720 J

    Heat to raise steam from 100 to 150

    2000 * 0.422 * 50 = 42200 J

    Thus the heat required is (135072.072 + 953720 + 42200) = 1330992.07 Joules or 1330 kilo joules
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How much heat is required to convert 422 g of liquid h2o at 23.5 °c into steam at 150 °c? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers