The molarity (M) of an aqueous solution containing 15.6 g of sucrose, C12H22O11, in 65.5 mL of solution is:

6.96 x 10-4 M.

2.47 x 10-2 M.

0.696 M.

1.33 M.

Question

Gia Robbins

Chemistry

23 January, 11:23

The molarity (M) of an aqueous solution containing 15.6 g of sucrose, C12H22O11, in 65.5 mL of solution is:

6.96 x 10-4 M.

2.47 x 10-2 M.

0.696 M.

1.33 M.

+3

Answers (1)

Know the Answer?

Carlos Paul · Answer 1

the molecularity of C12H22O11 is = 12x12+22x1+16x11 = 342 g/mol

molarity (M) = moles / V. solution

moles = mass / 342 = 15,6/342 = 0,0456 moles

=> molarity (M) = 0,0456/0,0655 = 0,696 M

The molarity (M) of an aqueous solution containing 15.6 g of sucrose, C12H22O11, in 65.5 mL of solution is:6.96 x 10-4 M.2.47 x 10-2 M.0.696 M.1.33 M.

The molarity (M) of an aqueous solution containing 15.6 g of sucrose, C12H22O11, in 65.5 mL of solution is:

6.96 x 10-4 M.

2.47 x 10-2 M.

0.696 M.

1.33 M.