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23 January, 11:23

The molarity (M) of an aqueous solution containing 15.6 g of sucrose, C12H22O11, in 65.5 mL of solution is:

6.96 x 10-4 M.

2.47 x 10-2 M.

0.696 M.

1.33 M.

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  1. 23 January, 11:29
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    the molecularity of C12H22O11 is = 12x12+22x1+16x11 = 342 g/mol

    molarity (M) = moles / V. solution

    moles = mass / 342 = 15,6/342 = 0,0456 moles

    => molarity (M) = 0,0456/0,0655 = 0,696 M
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