When limestone (calcium carbonate) is strongly heated, it breaks down into calcium oxide and carbon dioxide. If 88 grams of carbon dioxide is released when 200 grams of limestone is heated, how much calcium oxide is produced in this reaction? A. 56 grams B. 88 grams C. 112 grams D. 200 grams

Answer: C. 112 grams

Using the law of conservation of mass, you can say that the total mass of the reactant would be equal to total mass of the product. The reactant of this reaction would be 200g CaCO3 (calcium carbonate). The product would be x g calcium oxide (CaO) and 88g carbon dioxide (CO2). The calculation would be:

reactant = product

200g = 88g + x

x = 200g-88g = 112g