A balanced chemical equation used to prepare ammonium carbonate, (nh4) 2co3, is: 2 n h 3 (g) + c o 2 (g) + h 2 o (l) ⟶ (n h 4) 2 c o 3 which choice of reactant quantities shown below would result in the greatest amount of ammonium carbonate being formed?

Question

Scott Cunningham

Chemistry

4 May, 02:14

A balanced chemical equation used to prepare ammonium carbonate, (nh4) 2co3, is: 2 n h 3 (g) + c o 2 (g) + h 2 o (l) ⟶ (n h 4) 2 c o 3 which choice of reactant quantities shown below would result in the greatest amount of ammonium carbonate being formed?

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Ezra Mckee · Answer 1

This a simple stoichiometry problem using the ideal gas law.

First take the grams of ammonium carbonate and convert it to moles using its molar mass and dividing. 11.9 g/96.0932 g/mol=.12384 mol

Now use a molar conversion using the balanced equation,

1 mol (NH4) 2CO3 - --> 4 mol gas formed (2 mol NH3 + 1 mol CO2 + 1 mol H2O) =.12384 x 4 =.49535 mol gas

PV=nRT

V=nRT/P=.49535mol (.08206 Lxatm/molxK) (296K) / (1.03 atm) = 11.682 L