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1 June, 02:36

An iron block of mass 18 kg is heated from 285 K to 318 K. If 267.3 kJ is required, what is the specific heat of iron? A. 450.00 B. 145.80 C. 158.77 D. 490.05

I am looking for an ABC or D not a long list of explanations

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Answers (1)
  1. 1 June, 02:57
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    Option A. 450.00

    Explanation:

    1) dа ta:

    a) m = 18 kg

    b) T₁ = 285 K

    c) T₂ = 318 K

    d) Q = 267.3 kJ

    e) S = ?

    2) Principles and equations

    The specific heat of a substance is the amount of heat energy absorbed to increase the temperature of certain amount (gram, kg, or moles, depending on the definition or units) of the substance in 1 ° C or 1 K.

    The mathematical relation between the specific heat and the heat energy absorbed is:

    Q = m * S * ΔT

    Where,

    Q is the heat absorbed, S is the specific heat, and ΔT is the temperature increase (T₂ - T₁)

    3) Solution:

    a) Substitute the data into the equation:

    267.3 kJ = 18 kg * S * (318 K - 285 K)

    b) Solve for S and compute:

    S = 267.3 kJ / (18 kg * 33 K) = 0.45 kJ / (Kg. K)

    The options have not units, but I notice that the first answer is 1,000 times the answer I obtained, so I will make a conversion of units.

    c) Convert to J / (kg. k):

    0.45 kJ / (Kg. K) * 1,000 J / kJ = 450 J / (kg. K)

    Now we can see that the option A is is the answer, assuming the units.
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