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19 July, 12:32

A cast iron grate is used to sear "grill marks" into food. If the grate has a heat capacity of 458.5 J/K, how much heat must be added to the grate to heat it from 292.5K to 459.7K?

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  1. 19 July, 12:55
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    2.74 Joules

    Explanation:

    The heat capacity of the metal is the amount of heat needed to raise the temperature of the metal by 1 k

    heat capacity c of the sear grill = 458.5 J/K

    initial temperature T1 = 292.5 K

    final temperature T2 = 459.7 K

    temperature change ΔT = 459.7 - 292.5 = 167.2 K

    since the heat capacity is heat energy needed per degree rise in Kelvin, then the heat to raise the metal by this temperature change will be

    heat required = c/ΔT = 458.5/167.2 = 2.74 Joules
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