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26 May, 23:02

a mixture is made up of 3.35g of SiO2, 0.38g of cellulose and 8.76g of calcium carbonate. What is the percent of cellulose in the sample?

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  1. 26 May, 23:07
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    Solution:

    mass of the cellulose in the mixture is 0.38g

    total mass of the mixture is:

    3.35+0.38+8.76

    =12.4g

    thus the percentage of the cellulose in the mixture is:

    mass of the cellulose/total mass of the mixture*100%

    0.38/12.4*100%

    =3%
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