A student placed 19.0 g of glucose (c6h12o6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-ml mark on the neck of the flask was reached. the flask was then shaken until the solution was uniform. a 45.0-ml sample of this glucose solution was diluted to 0.500 l. how many grams of glucose are in 100. ml of the final solution? express your answer numerically in grams.

Question

Rohan Hampton

Chemistry

16 November, 21:40

A student placed 19.0 g of glucose (c6h12o6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-ml mark on the neck of the flask was reached. the flask was then shaken until the solution was uniform. a 45.0-ml sample of this glucose solution was diluted to 0.500 l. how many grams of glucose are in 100. ml of the final solution? express your answer numerically in grams.

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Avery Curtis · Answer 1

moles glucose = 19 g / 180 g/mol = 0.105

M = 0.105 / 0.100 L = 1.05

moles in 20.0 mL = 1.05 M x 0.0200 L = 0.0216

New concentration = 0.0216 / 0.500 L = 0.0432 M

moles in 100 mL = 0.100 L x 0.0432 = 0.00432

mass = 0.00432 x 180 g/mol = 0.778 g