An automobile tire is inflated to a pressure of 3.05 atm on a rather warm day when the temperature is 40 C. The car is then driven to the mountains and parked overnight. The morning temperature is - 5.0 C (five below zero). What will the pressure of the gas be in the tire at this temperature? Assume the volume of the tire doesn't change.

Question

Adrianna Mills

Chemistry

12 October, 20:02

An automobile tire is inflated to a pressure of 3.05 atm on a rather warm day when the temperature is 40 C. The car is then driven to the mountains and parked overnight. The morning temperature is - 5.0 C (five below zero). What will the pressure of the gas be in the tire at this temperature? Assume the volume of the tire doesn't change.

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Bart · Answer 1

P1 = 3.05atm, T1 = 40C, T2 = - 5.0C

T1 = 273+40 = 313K, T2=273K-5.0C = 268K

Use P1V1/T1 = P2V2/T2, but V1=V2 so they cancel each other out:

P1/T1 = P2/T2 - - > P2 = P1T2/T1

P2 = (3.05) (268) / 313 = 2.61 atm