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20 February, 22:20

What is the density of oxygen gas (O2) at 2.3 atmospheres and 305 Kelvin? Show all of the work used to solve this problem.

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  1. 20 February, 22:38
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    2.94g/L

    Explanation:

    First, let us derive an expression for the density, using the ideal gas equation:

    PV = nRT (1)

    V = nRT / P (2)

    Recall:

    Number of mole (n) = mass (m) / Molar Mass (M)

    n = m/M

    Substituting the value of n into equation 2:

    V = nRT / P

    V = mRT / MP

    Now Divide both side by m

    V/m = RT / MP

    Inverting the above equation, we have:

    m/V = MP/RT

    But Density = m/V

    Density = MP/RT

    From the question given, we obtained the following dа ta:

    P = 2.3atm

    T = 305K

    Molar Mass of O2 = 16x2 = 32g/mol

    R = 0.082atm. L/K / mol

    Density = (32x2.3) / (0.082x305)

    Density = 2.94g/L
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