Calculate the molality of a 1.06 M sucrose, C12H22O11, with a density of 1.14 g/mL. For sucrose, mol. wt.

Question

Howie

Chemistry

18 November, 19:22

Calculate the molality of a 1.06 M sucrose, C12H22O11, with a density of 1.14 g/mL. For sucrose, mol. wt.

+3

Answers (1)

Know the Answer?

Eleanor Roach · Answer 1

The molality is 0.930 mol/kg

Explanation:

Molality = molarity : density

Molarity of sucrose = 1.06 M = 1.06 mol/L

Density of sucrose = 1.14 g/mL = 1.14 g/mL * 1 kg/1000 g * 1 mL / 0.001 L = 1.14 kg/L

Molality = 1.06 mol/L : 1.14 kg/L = 0.930 mol/kg