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26 February, 13:31

Calculate the mole fraction of benzene in a mixture that contains 45.2 g of benzene and 115.8 g of toluene.

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  1. 26 February, 13:36
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    molecular weight of toluene = 92 g/mol

    C6 = 12 x 6 = 72

    H5 = 1 x 5 = 5

    CH3 = 12 + 1 x 3 = 15

    molecular weight of benzene = 78 g/mol

    C6 = 12 x 6 = 72

    H6 = 1 x 6 = 6

    moles toluene:

    115.8 / (92 g/mol) = 1.25 mol

    moles benzene:

    45.2 / (78 g/mol) = 0.57mol

    total moles: 1.25 + 0.57 = 1.82 moles

    mole fraction of toluene:

    1.25 mol / 1.82 moles = 0.68
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