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13 October, 14:37

In the following reaction, which component acts as an oxidizing agent? 10 I - (aq) + 2 MnO4 - (aq) + 16 H + (aq) → 5 I2 (s) + 2 Mn2 + (aq) + 8 H2O (l)

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  1. 13 October, 14:46
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    The oxidizing agent is the MnO₄⁻

    Explanation:

    This is the redox reaction:

    10 I⁻ (aq) + 2 MnO₄⁻ (aq) + 16 H⁺ (aq) → 5 I₂ (s) + 2 Mn²⁺ (aq) + 8 H2O (l)

    Let's determine the oxidation and the reduction.

    I⁻ acts with - 1 in oxidation state and changes to 0, at I₂.

    All elements in ground state has 0 as oxidation state.

    As the oxidation state has increased, this is the oxidation, so the iodide is the reducing agent.

    In the permanganate (MnO₄⁻), Mn acts with + 7 in oxidation state and decreased to Mn²⁺. As the oxidation state is lower, we talk about the reduction. Therefore, the permanganate is the oxidizing agent because it oxidizes iodide to iodine
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