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3 June, 01:24

Determine the specific heat of a mayterial if a 35g sample of the material absorbs 48J as it is heated from 298K to 313K

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  1. 3 June, 01:34
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    dа ta:

    m = 35g

    Q = 48 j

    T1 = 298K

    T2 = 313K

    Cs = ?

    Fórmula: Q = m*Cs * (T2 - T1) = > Cs = Q / [m (T2 - T1) ]

    Cs = 48 j / [35g (313K - 298K] = 0.0914 j / g*K = 91.4 j / kg*K
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