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21 June, 20:50

A 3.60 l gas sample is at a pressure of 95.5 kpa and a temperature of 25.0°c. if the gas sample weighs 6.10 g, calculate the molar mass of the gas.

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  1. 21 June, 21:00
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    Strategy of solution:

    First, find the number of moles of the gas using the law pV = nRT. After that, find the molar mass by dividing the mass of the compound by the number of moles: molar mass = n / mm

    Solution:

    1)

    p = 95.5 kPa

    T = 25.0 + 273.15 K = 298.15 K

    V = 3.60 l

    R = 8.314 (l * kPa / K*mol)

    => n = pV / RT = [95.5 kPa * 3.60 l ] / [8.314 (l*kPa/K*mol) * 298.15 K] = 0.139 mol

    2) mm = number of grams / number of moles = 6.10 g / 0.139 mol = 43.88 g/mol

    Answer: 43.9 g / mol (rounded to three significant figures)
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