If a chemist wishes to dilute a 1.000 x 103 mg/l stock solution to prepare 5.000 x 102 ml of a working standard that has a concentration of 6.250 mg/l, what volume of the 1.000 x 103 mg/l standard solution is needed?

Question

Dalton Phillips

Chemistry

1 May, 13:53

If a chemist wishes to dilute a 1.000 x 103 mg/l stock solution to prepare 5.000 x 102 ml of a working standard that has a concentration of 6.250 mg/l, what volume of the 1.000 x 103 mg/l standard solution is needed?

+5

Answers (1)

Know the Answer?

Zaiden Hudson · Answer 1

Given dа ta:

Concentration of stock solution which is the initial solution = M1 = 1.00 * 10^3 mg/L

Concentration of prepared solution i. e final solution = M2 = 6.250 mg/L

Volume of final solution, V2 = 5.000 * 10^2 ml

To determine:

The initial volume i. e. volume of the stock solution required = V1

Calculation:

Use the relation

M1V1 = M2V2

V1 = M2V2/M1 = 6.250 mg. L-1 * 5.000*10^2 ml/1.00 * 10^3 mg. L-1

V1 = 3.125 * 10^3 ml

The volume of stock solution required is 3.125 * 10^3 ml