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9 May, 23:47

A 150ml sample of hydrochloric acid completely reacted with 60.0mL of a 0.100 M NaOH solution. What was the original concentration of the HCl solution

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  1. 10 May, 00:04
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    HCl + NaOH = NaCl + H₂O

    n (HCl) = c (HCl) v (HCl)

    n (NaOH) = c (NaOH) v (NaOH)

    n (HCl) = n (NaOH)

    c (HCl) v (HCl) = c (NaOH) v (NaOH)

    c (HCl) = c (NaOH) v (NaOH) / v (HCl)

    c (HCl) = 0.100mmol/mL*60.0mL/150mL=0.040 mmol/mL = 0.040 mol/L

    0.040 M HCl
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