What is the pressure of 0.540 mol of an ideal gas at 35,5 L and 223 K?

Use PV = nRT and R = 8.314 okPa

molok

0.715 kPa

2.45 kPa

28.2 kPa

62.7 kPa

Mark this and return

Answer:c

P = 28.2 Kpa

Explanation:

Given dа ta:

Volume = 35.5 L

Temperature = 223 K

Number of moles = 0.540 mol

R = 8.314 Kpa. L/mol. K

Pressure = ?

Solution:

PV = nRT

P = nRT / V

P = 0.540 mol. 8.314 Kpa. L/mol. K. 223 K / 35.5 L

P = 1001.2 Kpa. L / 35.5 L

P = 28.2 Kpa