Calculate the volume of a 1.420 m naoh solution required to titrate 34.55 ml of a 1.500 m h3po4 solution.

Step 1; write the equation for reaction

the equation for reaction is as follows

NaOH + H3PO4 - - - > Na2 PO4 + H2o

then calculate the moles of H3PO4 used

that is 34.55 x1.500/1000 = 0.052 moles

by use of mole ratio between NaOH to H3Po4 which is 1:1 the moles of NaOh = 0.052 moles

volume of NaOh is = moles of NaOH / molarity

that is 0.052 / 1.420=0.03662 L

in Ml = 0.03662 x1000=36.62 Ml