What mass of propane is necessary to react with the amount of oxygen in the chemical formula C3H8 + 5O2 → 3CO2 + 4H2O

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Kyler

Chemistry

25 December, 15:51

What mass of propane is necessary to react with the amount of oxygen in the chemical formula C3H8 + 5O2 → 3CO2 + 4H2O

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Carley Hurst · Answer 1

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

n (O₂) = 1.407 mol

M (C₃H₈) = 44.1 g/mol

m (C₃H₈) / M (C₃H₈) = n (O₂) / 5

m (C₃H₈) = M (C₃H₈) n (O₂) / 5

m (C₃H₈) = 44.1*1.407/5=12.410 g

the mass of propane is 12.410 g