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30 June, 10:41

A gas is contained in a thick-walled

balloon. When the pressure changes

from 18.7 psi to 20.2 psi, the volume

changes from 0.475 L to 1.054 L and

the temperature changes from

K to 465 K.

+2
Answers (1)
  1. 30 June, 10:49
    0
    T₁ = 194 K

    Solution:

    Data Given:

    Initial Temperature = T₁ = ?

    Final Temperature = T₂ = 465 K

    Initial Pressure = P₁ = 18.7 psi

    Final Pressure = P₂ = 20.2 psi

    Initial Volume = V₁ = 0.475 L

    Final Volume = V₂ = 1.054 L

    Formula Used:

    Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,

    P V = n R T

    where; R = Universal Gas Constant = 0.082057 atm. L. mol⁻¹. K⁻¹,

    Taking number of moles and R constant we can have following formula for initial and final states,

    P₁ V₁ / T₁ = P₂ V₂ / T₂

    Solving for T₁,

    T₁ = P₁ V₁ T₂ / P₂ V₂

    Putting values,

    T₁ = (18.7 psi * 0.475 L * 465 K) / (20.2 psi * 1.054 L)

    T₁ = 194 K
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