How many grams of aluminum are required to give a total dislocation length of 3,000 miles (enough to stretch from New York City to Los Angeles assuming you could align all the dislocations into a single line like a string). Assume the dislocation density of aluminum is 1010cm/cm3.

Question

Jackrabbit

Chemistry

11 July, 11:28

How many grams of aluminum are required to give a total dislocation length of 3,000 miles (enough to stretch from New York City to Los Angeles assuming you could align all the dislocations into a single line like a string). Assume the dislocation density of aluminum is 1010cm/cm3.

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Answers (1)

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Dixon · Answer 1

0.13 g

Explanation:

mass of aluminum required = (Dislocation length) / (Dislocation density) * (density of metal)

3000 miles to cm (1 mile = 160934 cm) = 3000 miles * 160934 cm / 1 mile = 482802000 cm

density of Aluminium = 2.7 g / cm³

dislocation density of aluminum = 10¹⁰ cm³

mass of aluminum required = (482802000 cm * 2.7 g/cm³) / 10¹⁰ cm³ = 0.13 g