Consider the reaction between no and cl2 to form nocl: 2no (g) + cl2 (g) ⇌2nocl (g) a reaction mixture at a certain temperature initially contains only [no] = 0.65 m and [cl2] = 0.53. after the reaction comes to equilibrium, the concentration of nocl is 0.30 m. part a find the value of the equilibrium constant (kc) at this temperature.

Question

Devan Hale

Chemistry

4 February, 06:57

Consider the reaction between no and cl2 to form nocl: 2no (g) + cl2 (g) ⇌2nocl (g) a reaction mixture at a certain temperature initially contains only [no] = 0.65 m and [cl2] = 0.53. after the reaction comes to equilibrium, the concentration of nocl is 0.30 m. part a find the value of the equilibrium constant (kc) at this temperature.

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Answers (1)

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Lola Marsh · Answer 1

Kc = 0.402.

Explanation:

We can calculate Kc from the relation: Kc = [NOCl]² / [NO]²[Cl₂]. [NOCl] = 0.30 M, [NO] = 0.65 M, and [Cl₂] = 0.53 M. Now, we can get Kc: Kc = [NOCl]² / [NO]²[Cl₂] = (0.30 M) ² / [ (0.65 M) ². (0.53 M) ] = 0.402.