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24 September, 20:09

The Volume of a certain gas is 29.3 liters at STP. What would be the volume of the same gas at 1.39 atmospheres and - 23.0oC? (R = 0.0821 L. atm/mol. k)

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  1. 24 September, 20:22
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    V₂ = 19.30 L

    Explanation:

    Given dа ta:

    Initial volume of gas = 29.3 L

    Initial temperature = standard = 273 K

    Initial pressure = standard = 1 atm

    Final volume = ?

    Final temperature = - 23°C (-23+273 = 250 K)

    Final pressure = 1.39 atm

    Solution:

    Formula:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = Initial pressure

    V₁ = Initial volume

    T₁ = Initial temperature

    P₂ = Final pressure

    V₂ = Final volume

    T₂ = Final temperature

    Solution:

    V₂ = P₁V₁ T₂ / T₁ P₂

    V₂ = 1 atm * 29.3 L * 250 K / 273 K * 1.39 atm

    V₂ = 7325 atm. L. K / 379.47 K. atm

    V₂ = 19.30 L
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