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5 February, 17:22

When 3.05 moles of ch4 are mixed with 5.03 moles of 02 the limiting reactant is?

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  1. 5 February, 17:39
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    To determine the limiting reactant of a reaction, it is important first to know the balanced reaction. For this case, it is:

    CH4 + 2O2 = CO2 + 2H2O

    We determine as follows:

    3.05 mol CH4 (2 mol O2 / 1 mol CH4) = 6.1 mol O2 needed

    5.03 mol O2 (1 mol CH4 / 2 mol O2) = 2.515 mol CH4 needed

    Since the needed amount of CH4 is less than what is given, the O2 should be the limiting reactant since it would react completely.
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