Consider the reaction 2no2 (g) → n2o4 (g) and δg∘ (no2 (g)) = 51.84 kj/mol, δg∘ (n2o4 (g)) = 98.28 kj/mol. calculate δg at 298 k if the partial pressures of no2 and n2o4 are 0.38atm and 1.64atm, respectively.

Question

Alexa Campos

Chemistry

3 April, 03:55

Consider the reaction 2no2 (g) → n2o4 (g) and δg∘ (no2 (g)) = 51.84 kj/mol, δg∘ (n2o4 (g)) = 98.28 kj/mol. calculate δg at 298 k if the partial pressures of no2 and n2o4 are 0.38atm and 1.64atm, respectively.

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Payne · Answer 1

We can get ΔG from this formula:

ΔG = - R*T * (㏑K)

when K = p (N2O4) / p (NO2) ^2

we have P (N2O4) = 1.64 atm

and P (NO2) ^2 = 0.38 atm

by substitution:

=1.64 atm / (0.38) ^2

= 11.36

and R = 8.314

and T = 298 K

so by substitution on ΔG formula:

∴ ΔG = 8.314 * 298 * (㏑ 11.36)

= - 6020.7