Upon decomposition, one sample of magnesium fluoride produced 2.15 kg of magnesium and 3.36 kg of fluorine. A second sample produced 1.00 kg of magnesium. How much fluorine (in grams) did the second sample produce?

The second sample will produce 1563 grams of fluorine (F2)

Explanation:

The reaction will be MgF2 → Mg + F2

The stoichiometry ratio of MgF2 and F2 is 1 : 1.

That means for 1 mole of MgF2 consumed there is 1 mole of F2 produced.

The first sample produces 2.15 kg of magnesium and 3.36 kg of fluorine

The second sample produced 1 kg of magnesium and x kg of fluorine

This we can show in the following equation =

2.15kg / 3.36 kg = 1kg / x

2.15/3.36 = 0.63988

0.63988 = 1 / x

x = 1/0.63988 = 1.563 kg

1.563kg = 1563 grams

The second sample will produce 1563 grams of fluorine (F2)