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13 November, 01:41

How much energy is required to heat 250 grams of water from 20.0°C to 80.0°C? The heat capacity of water is 4.186 J/g°C

Q=mc∆T

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  1. 13 November, 01:45
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    62,790J

    Explanation:

    Q=mcT

    = 250g*4.186J/gc*80-20

    =250*4.186*60=62,790J
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