How many atoms are in 45.6 g gold, Au

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Duncan

Chemistry

27 July, 00:13

How many atoms are in 45.6 g gold, Au

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Kirsten Lynch · Answer 1

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

45.6 g Au (1 mol / 196.97 g) (6.022 x 10^23 atoms / mole) = 1.39x10^23 atoms Au