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27 May, 11:11

How many grams of chromium are required to react with 125ml of 0.75m cuso4?

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  1. 27 May, 11:32
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    Chromium and copper (ii) sulfate react according the reaction below;

    2Cr + 3CuSO4 = 3Cu + Cr2 (SO4) 3

    We can calculate the number of moles of CuSO4 present;

    no of moles of CuSO4 = 0.75 * 0.125 = 0.09735 moles

    According to the reaction the mole ratio is 2 : 3

    Moles of Chromium = (0.09735 * 2) / 3

    = 0.0625 Moles

    Mass of chromium = 0.0625 moles * 52 g/mole

    = 3.25 g of chromium
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