If 12.1 kilograms of al2o3 (s), 60.4 kilograms of naoh (l), and 60.4 kilograms of hf (g) react completely, how many kilograms of cryolite will be produced?

Question

Chris Nielsen

Chemistry

1 October, 08:57

If 12.1 kilograms of al2o3 (s), 60.4 kilograms of naoh (l), and 60.4 kilograms of hf (g) react completely, how many kilograms of cryolite will be produced?

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Answers (1)

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Jeremy Keith · Answer 1

Answer is: 7,826 kg of cryolite.

Chemical reaction: Al₂O₃ + 6NaOH + 12HF → 2Na₃AlF₆ + 9H₂ O.

m (Al₂O₃) = 12,1 kg = 12100 g.

n (Al₂O₃) = m (Al₂O₃) : M (Al₂O₃).

n (Al₂O₃) = 12100 g : 101,96 g/mol = 111,86 mol; limiting reactant.

m (NaOH) = 60,4 kg = 60400 g.

n (NaOH) = 60400 g : 40 g/mol.

n (NaOH) = 1510 mol.

m (HF) = 60,4 kg = 60400 g.

n (HF) = 60400 g : 20 g/mol = 3020 mol.

From chemical reaction: n (Al₂O₃) : n (Na₃AlF₆) = 6 : 2.

n (Na₃AlF₆) = 2 ·111,86 mol : 6 = 37,28 mol.

m (Na₃AlF₆) = 37,28 mol · 209,94 g/mol.

m (Na₃AlF₆) = 7826,56 g = 7,826 kg.