If 12.1 kilograms of al2o3 (s), 60.4 kilograms of naoh (l), and 60.4 kilograms of hf (g) react completely, how many kilograms of cryolite will be produced?

Question

Chris Nielsen

Chemistry

Today, 08:57

If 12.1 kilograms of al2o3 (s), 60.4 kilograms of naoh (l), and 60.4 kilograms of hf (g) react completely, how many kilograms of cryolite will be produced?

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Answers (1)

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Jeremy Keith · Answer 1

Answer is: 7,826 kg of cryolite.

Chemical reaction: Al₂O₃ + 6NaOH + 12HF → 2Na₃AlF₆ + 9H₂ O.

m (Al₂O₃) = 12,1 kg = 12100 g.

n (Al₂O₃) = m (Al₂O₃) : M (Al₂O₃).

n (Al₂O₃) = 12100 g : 101,96 g/mol = 111,86 mol; limiting reactant.

m (NaOH) = 60,4 kg = 60400 g.

n (NaOH) = 60400 g : 40 g/mol.

n (NaOH) = 1510 mol.

m (HF) = 60,4 kg = 60400 g.

n (HF) = 60400 g : 20 g/mol = 3020 mol.

From chemical reaction: n (Al₂O₃) : n (Na₃AlF₆) = 6 : 2.

n (Na₃AlF₆) = 2 ·111,86 mol : 6 = 37,28 mol.

m (Na₃AlF₆) = 37,28 mol · 209,94 g/mol.

m (Na₃AlF₆) = 7826,56 g = 7,826 kg.