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1 March, 15:22

Calculate the number of moles of caco3 (calcium carbonate, or limestone) in a 20.0g sample of this substance

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  1. 1 March, 15:41
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    First calculate for the molar mass of the given formula unit, CaCO₃. This can be done by adding up the product when the number of atom is multiplied to its individual molar mass as shown below.

    molar mass of CaCO₃ = (1 mol Ca) (40 g Ca/mol Ca) + (1 mol C) (12 g of C/1 mol of C) + (3 mols of O) (16 g O/1 mol O) = 100 g/mol of CaCO₃

    Then, divide the given amount of substance by the calculated molar mass.

    number of moles = (20 g) (1 mol of CaCO₃/100 g)

    number of moles = 0.2 moles of CaCO₃

    Answer: 0.2 moles
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