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15 March, 14:42

A chemist reacts H2 with excess N2. The reaction yields 60 grams of NH3. however, you calculaye you should have recovered 80 grams of NH3. What is the percent yield of the reaction?

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  1. 15 March, 14:54
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    Percent yield = 75%

    Explanation:

    Given dа ta:

    Actual yield of ammonia = 60 g

    Theoretical yield of ammonia = 80 g

    Percent yield = ?

    Solution:

    Percent yield is calculated dividing the actual yield by theoretical yield and multiply by 100.

    Formula:

    Percent yield = Actual yield / Theoretical yield * 100

    Now we will put the values in formula.

    Percent yield = 60 g / 80 g * 100

    Percent yield = 0.75 * 100

    Percent yield = 75%

    So if the reaction yield is 60 g and calculated yield (theoretical yield) is 80 g then the percent yield would be 75%.
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