Consider the reaction 2 al + Fe2O3 to 2Fe + Al2O3. If 60.0g of Al is reacted with excess Fe2O3, determine the amount (in moles) and mass (in grams) of Al2O3 produced

The amount of Al2O3 in moles = 1.11 moles while in grams = 113.22 grams

calculation

2 Al + Fe2O3 → 2Fe + Al2O3

step 1: find the moles of Al by use of moles = mass/molar mass formula

= 60.0/27 = 2.22 moles

Step 2: use the mole ratio to determine the moles of Al2O3.

The mole ratio of Al : Al2O3 is 2: 1 therefore the moles of Al2O3 = 2.22/2=1.11 moles

Step 3: finds the mass of Al2O3 by us of mass = moles x molar mass formula.

The molar mass of Al2O3 = (2x27) + (16 x3) = 102 g/mol

mass is therefore = 102 g/mol x 1.11 = 113.22 grams