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4 March, 08:24

A sample of an unknown compound is vaporized at 170 (degrees) C. The gas produced has a volume of 1980. mL at a pressure of 1.00atm, and it weighs 5.17g.

Assuming the gas behaves as an ideal gas under these conditions, calculate the molar mass of the compound. Round your answer to 3 significant digits. In g/mol.

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  1. 4 March, 08:49
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    The answer to your question is: 0.28 g/mol

    Explanation:

    Data

    T = 170°C = 443°K

    V = 1980 ml

    P = 1 atm

    m = 5.17 g

    R = 0.082 (atm l) / (mol°K)

    Formula

    PV = nRT

    Process

    n = RT / PV

    Substitution

    n = (0.082 x 443) / (1 x 1.98 l)

    n = 36.33 / 1.98

    n = 18.35 moles

    Molar mass = 5.17 / 18.35

    = 0.28 g/mol
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