The activation energy for the gas phase isomerization of cyclopropane is 272 kJ. (CH2) 3CH3CH=CH2 The rate constant at 718 K is 2.30*10-5 / s. The rate constant will be / s at 753 K.

Question

Charles Bonilla

Chemistry

14 August, 12:16

The activation energy for the gas phase isomerization of cyclopropane is 272 kJ. (CH2) 3CH3CH=CH2 The rate constant at 718 K is 2.30*10-5 / s. The rate constant will be / s at 753 K.

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Camron Garza · Answer 1

Answer is:rate constant will be 2,27·10⁻⁴ 1/s.

Arrhenius equation: ln (k₁/k₂) = Ea/R (1/T₂ - 1/T₁).

k₁ = 0000023 1/s.

k₂ = ?

T₁ = 718 K.

T₂ = 753 K.

R = 8,3145 J/Kmol.

Ea = 272 kJ.

1/T₁ = 1/718 K = 0,0014 1/K.

1/T₂ = 1/753 K = 0,00133 1/K.

ln (0,000023/k₂) = 272000 J/8,3145 J/Kmol · (-0,00007 1/K).

ln (0,000023/k₂) = - 2,29

0,000023/k₂ = 0,101.

k₂ = 0,000227 1/s.