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28 June, 06:51

Suppose 14 quarts of a solution that is 36% antifreeze is mixed with 6 quarts of a solution that is 12% antifreeze.

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  1. 28 June, 07:07
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    Missing question:

    1. How many quarts of antifreeze are in the resulting mixture?

    2. What % of the resulting mixture is antifreeze?

    1) V₁ = 14 qt; volume of solution.

    ω₁ = 36% : 100% = 0.36.

    V₂ = 6 qt.

    ω₂ = 12% : 100% = 0.12.

    V₃ = V₁ · ω₁ + V₂ · ω₂.

    V₃ = 14 qt · 0.36 + 6 qt · 0.12.

    V₃ = 5.76 qt; quarts of antifreeze in the resulting mixture.

    2) ω₃ = V₃ / (V₁ + V₂) · 100%.

    ω₃ = 5.76 qt / (14 qt + 6 qt) · 100%.

    ω₃ = 28.8 %; % of the resulting mixture is antifreeze.
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