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13 December, 02:02

A student calculated the density of a sample of graphite to be 2.3 g/cm3. Show a numerical setup for calculating the student's percent error for the density of graphite.

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  1. 13 December, 02:13
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    Percent error = 1.5%

    Explanation:

    Given dа ta:

    Measured value of density of graphite = 2.3 g/cm³

    Percent error = ?

    Solution:

    Formula:

    Percent error = [Measured value - Actual value / actual value] * 100

    Actual/accepted value of density of graphite = 2.266 g/cm³

    Now we will put the values:

    Percent error = [2.3 g/cm³ - 2.266 g/cm³ / 2.266 g/cm³] * 100

    Percent error = [0.034 g/cm³ / 2.266 g/cm³] * 100

    Percent error = 0.015 * 100

    Percent error = 1.5%
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