It is found that 250 ml of gas at stp has a mass of. 675 g what is the molar mass

61.3 g/mol

Step-by-step explanation:

We can use the Ideal Gas Law to solve this problem:

pV = nRT

Since n = m/M, the equation becomes

pV = (m/M) RT Multiply each side by M

pVM = RT Divide each side by RT

M = (mRT) / (pV)

dа ta:

m = 0.675 g

R = 0.0.083 14 bar·L·K⁻¹mol⁻¹

T = 0 °C = 273.15 K

p = 1 bar

V = 250 mL = 0.250 L

Calculation:

M = (0.675 * 0.083 14 * 273.15) / (1 * 0.250)

M = 15.33/0.250

M = 61.3 g/mol